将短的字符串前面补充0，使两字符串对其再进行加法：

class Solution {
public:string addBinary(string a, string b) {int n=a.size();int m=b.size();if(n>m) b.insert(0,n-m,'0');else if(m>n) a.insert(0,m-n,'0');string c;int jw=0;for(int i=max(n,m)-1;i>=0;i--){cout<<a[i]<<" "<<b[i]<<endl;int cc=(a[i]+b[i]+jw-96)%2;jw=(a[i]+b[i]+jw-96)/2;cout<<cc<<" "<<jw<<endl;c.insert(c.begin(),cc+48);}if(jw==1) c.insert(c.begin(),jw+48);return c;}
};